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The nth term of an ap is 3n – 2

WebJun 25, 2024 · Nth term of an A.P. ⇒ aₙ = 3n - 2. As we know that, Put the value of n = 1 in the equation, we get. ⇒ 3(1) - 2. ⇒ 3 - 2 = 1. Put the value of n = 2 in the equation, we get. … Webn th Term of an AP Formula Assume that a 1, a 2, a 3 ,… be an arithmetic progression (AP), in which first term a 1 is equal to “a” and the common difference is taken as “d”, then the second term, third term, etc can be calculated as follows: Second term, a 2 = a+d Third …

Write fourth term of AP whose nth term in 3n+2 - Brainly

WebMock Tests; Mock Tests; Aptitude and Reasoning; General Knowledge; Puzzles; Interviews; Technical WebThe sum of the first n terms of an AP is (5n 2 /2 +3n/2). Find its nth term and the 20th term of this AP. arithmetic progression class-10 1 Answer +2 votes answered Sep 14, 2024 by AmirMustafa (60.4k points) selected Sep 23, 2024 by Vikash Kumar Best answer Hence, the 20th term is 99. ← Prev Question Next Question → Find MCQs & Mock Test symmetry scout rifle https://fridolph.com

Example 6 - Sum of n terms of two APs are in ratio (3n + 8) - teachoo

WebMar 22, 2024 · Ex 9.2,13 If the sum of n terms of an A.P. is 3n2 + 5n and its mth term is 164, find the value of m. Let a1, a2, … an be the given A.P Given, Sum of n terms = 3n2 + 5n Sn = 3n2 + 5n Putting n = 1 in (1) S1 = 3 × 12 + 5 × 1 = 3 × 1 + 5 × 1 = 3 + 5 = 8 Sum of first 1 terms = First term ∴ First term = a1 = S1 = 8 Sn = 3n2 + 5n … WebFeb 25, 2024 · Step-by-step explanation: We require to find the first term a₁ and the common difference d. The n th term is given by 3n + 2, thus. a₁ = 3 (1) + 2 = 3 + 2 = 5. a₂ = 3 (2) + 2 … WebIf S n, the sum of first n terms of an AP is given by Sn = 3n 2 - 4n, find the nth term. Advertisement Remove all ads Solution We have, S n = 3n 2 - 4n for n = 1 ⇒ S 1 = 3 ( 1) 2 - 4 ( 1) = 3 - 4 = - 1 ⇒ a 1 = S1 = -1 for n = 2 ⇒ S 2 = 3 ( 2) 2 - 4 ( 2) = 12 - 8 = 4 S 2 = 4 a 2 = S 2 - S 2 = 4 - (-1) a 2 = 5 Common difference, d = a 2 - a 1 symmetry screens

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The nth term of an ap is 3n – 2

The sum of the first n terms of an AP is given by Sn = (3n^2 - Toppr

WebThe sum of the first n terms of an AP is given by Sn=(3n 2−n). Find its nth term. Medium Solution Verified by Toppr We know, n th term a n=a+(n−1)d Where a= First term d= Common difference n= number of terms a n=n th term Given, S n=3n 2−n S 1=3(1) 2−1=3−1=2 S 2=3(2) 2−2=12−2=10 a 1=2 a 2=S 2−S 1=10−2=8 a n=a+(n−1)d =2+(n−1)×6 … WebThe nth term for a quadratic sequence has a term that contains \ (x^2\). Terms of a quadratic sequence can be worked out in the same way. Example Write the first five terms of the...

The nth term of an ap is 3n – 2

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WebThe nth term of a sequence is 3n-2. Is the sequence an A.P. ? If so, find its 10th term . Easy Solution Verified by Toppr a n=3n−2 a n is a linear expression in n. So, the given sequence … WebJan 19, 2024 · The `n^ (th)` term of the sequence is `3n-2` . Is the sequence an AP. If so; find the 10th term . Doubtnut 2.64M subscribers 8.7K views 3 years ago The `n^ (th)` term of …

WebStep 1: Subtract first and second sum to find second term Given sum of n terms of AP is 2 n + 3 n 2 … (i) Put n = 1 in (i) S 1 = 2 + 3 = 5 Here, S 1 is the sum up to first term So first term … WebMar 17, 2024 · Given sequence whose a n = 3n + 2. To get the first five terms of given sequence, put n = 1, 2, 3, 4, 5 and we get. a 1 = (3 × 1) + 2 = 3 + 2 = 5. a 2 = (3 × 2) + 2 = 6 + …

WebDec 26, 2024 · The fourth term of AP whose nth term is 3n + 2 is 14. Given : The AP whose nth term is 3n + 2. To find : The fourth term of the AP . Solution : Step 1 of 2 : Write down the given data . Here it is given that for the AP nth term is 3n + 2 . Step 2 of 2 : Find fourth term of AP . Putting n = 4 in the given AP we get . ⇒ Fourth term = ( 3 × 4 ) + 2

WebThus, the formula of nth term of ap is, T n = a + (n - 1)d This relation helps us calculate any term of an AP, given its first term (a) and its common difference (d). Thus, for the AP that …

WebJul 25, 2024 · Lesson 3: nth term of an AP. Nth term of an arithmetic progression. Arithmetic sequence problem. nth term of an arithmetic progression (basic) ... Its bcoz, (Ref=n/2) the sum of any 2 terms of … symmetry securityWebApr 11, 2024 · To find the N th term in the Arithmetic Progression series we use the simple formula . T N = a 1 + (N-1) * d Recommended: Please try your approach on {IDE} first, … thackery washerWebOct 16, 2024 · Best answer Sn = 3n2 + 2n Taking n = 1, we get S1 = 3 (1)2 + 2 (1) ⇒ S1 = 3 + 2 ⇒ S1 = 5 ⇒ a1 = 5 Taking n = 2, we get S2 = 3 (2)2 + 2 (2) ⇒ S2 = 12 + 4 ⇒ S2 = 16 ∴ a2 = S2 – S1 = 16 – 5 = 11 Taking n = 3, we get S3 = 3 (3)2 + 2 (3) ⇒ S3 = 27 + 6 ⇒ S3 = 33 ∴ a3 = S3 – S2 = 33 – 16 = 17 So, a = 5, d = a2 – a1 = 11 – 5 = 6 symmetry series 360 folio case for ipad proWebNov 20, 2013 · a 3 =3(3)+2=11. The AP with nth term as 3n+2 is 5,8,11,14,.... Here, a=5 and d=3. S 25 = [2x5+(25-1)3] = [10+72] =1025. Answered by 20 Nov, 2013, 03:57: AM Application Videos. This video explains the concept of how to find the nth term of a … symmetry sculpting crease blenderWebFind the sum of the first 25 terms of an A.P. whose nth term is given by an = 2−3n. Solution Given that, an =2−3n Putting the value of n =1 ,then a1= 2−(3× 1) = 2−3= −1 Putting the value of n =2 ,then a2=2−(3× 2) = 2−6 = −4 Therefore, a =−1 and d= −4−(−1) =−4+1 =−3 Sn = n 2(2a+(n−1)d) S25 = 25 2[2×(−1)+(25−1)(−3)] = 25 2[−2−72] = 25 2 ×(−74) thackery white bootsWebIf the sum of n terms of an AP is 3n 2 + 5n and the m th term of the AP is 164. Find the value of m. 27; 9; 10; 12; Answer ... Demo Classes Available* Enroll For Free Now. Detailed Solution Download Solution PDF. Concept: If a n is the nth term of an AP and S n is the sum of n terms of the same AP then. a n = S n - S n - 1. Calculation: Given ... symmetry security softwareWebThe sum of the first n terms of an AP is (3n 2+6n). Find the nth term and the 15 th term of this AP. Medium Solution Verified by Toppr We know, n th term T n=a+(n−1)d Where a= First term d= Common difference n= number of terms T n=n th term Given: S n=3n 2+6n S 1=3(1) 2+6×1=3+6=9 S 2=3(2) 2+6×2=12+12=24 T 2=S 2−S 1=24−9=15 d=15−9=6 a=9 thackery vanity fair first edition